纯ASP上传图像文件到数据库的最佳例子
发表于:2007-06-30来源:作者:点击数:
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IAmTrue 发表于2000-11-2 7:56:49 ASP地带 getfile.htm ------------------------- html head title保存图片到 数据库 /title /head body b p/b你可以找个图片试试,保存完毕后会有提示/p form METHOD=POST ENCTYPE=multipart/form-data ACTION=savetodb.asp
IAmTrue 发表于2000-11-2 7:56:49 ASP地带
getfile.htm
-------------------------
<html>
<head>
<title>保存图片到
数据库</title>
</head>
<body>
<b>
<p></b>你可以找个图片试试,保存完毕后会有提示</p>
<form METHOD="POST" ENCTYPE="multipart/form-data" ACTION="savetodb.asp">
<p>Email : <input NAME="email" VALUE="wang
cq@sina.com" size="20"><br>
Picture : <input TYPE="file" NAME="blob"><br>
<input TYPE="submit" NAME="Enter"> </p>
</form>
</body>
</html>
savetodb.asp
----------------------------------
<%
Response.Buffer = TRUE
Response.Clear
byteCount = Request.TotalBytes
RequestBin = Request.BinaryRead(byteCount)
Dim UploadRequest
Set UploadRequest = CreateObject("Scripting.Dictionary")
BuildUploadRequest RequestBin
email = UploadRequest.Item("email").Item("Value")
contentType = UploadRequest.Item("blob").Item("ContentType")
filepathname = UploadRequest.Item("blob").Item("FileName")
filename = Right(filepathname,Len(filepathname)-InstrRev(filepathname,"\"))
picture = UploadRequest.Item("blob").Item("Value")
@#Response.ContentType = contentType
@#Response.binaryWrite picture
set objCn = server.createobject("adodb.connection")
set objRst = server.createobject("adodb.recordset")
objCn.Open "upload"
objrst.Open "pic", objcn, 1,3,2
objrst.addnew
objrst.fields("filename")=filename
objrst.fields("type")="gif"
objrst.fields("what").appendchunk picture
objrst.update
response.write "<a href=showpic.asp?id=" & objrst("id") & ">第" & objrst("id") & "个图片。</a>"
objrst.close
objCn.close
set objrst=nothing
set objcn = nothing
%>
<!--#include file="upload.asp"-->
showpic.asp
----------------------------------------
<%
set objCn = server.createobject("adodb.connection")
set objRst = server.createobject("adodb.recordset")
objCn.Open "upload"
objrst.Open "select what from pic where id=" & request("id"), objcn
if not objrst.eof then
response.binarywrite objrst("what")
end if
objrst.close
objCn.close
set objrst=nothing
set objcn = nothing
%>
upload.asp
-------------------------------------------
<%
Sub BuildUploadRequest(RequestBin)
@#Get the boundary
PosBeg = 1
PosEnd = InstrB(PosBeg,RequestBin,getByteString(chr(13)))
boundary = MidB(RequestBin,PosBeg,PosEnd-PosBeg)
boundaryPos = InstrB(1,RequestBin,boundary)
@#Get all data inside the boundaries
Do until (boundaryPos=InstrB(RequestBin,boundary & getByteString("--")))
@#Members variable of objects are put in a dictionary object
Dim UploadControl
Set UploadControl = CreateObject("Scripting.Dictionary")
@#Get an object name
Pos = InstrB(BoundaryPos,RequestBin,getByteString("Content-Disposition"))
Pos = InstrB(Pos,RequestBin,getByteString("name="))
PosBeg = Pos+6
PosEnd = InstrB(PosBeg,RequestBin,getByteString(chr(34)))
Name = getString(MidB(RequestBin,PosBeg,PosEnd-PosBeg))
PosFile = InstrB(BoundaryPos,RequestBin,getByteString("filename="))
PosBound = InstrB(PosEnd,RequestBin,boundary)
@#Test if object is of file type
If PosFile<>0 AND (PosFile<PosBound) Then
@#Get Filename, content-type and content of file
PosBeg = PosFile + 10
PosEnd = InstrB(PosBeg,RequestBin,getByteString(chr(34)))
FileName = getString(MidB(RequestBin,PosBeg,PosEnd-PosBeg))
@#Add filename to dictionary object
UploadControl.Add "FileName", FileName
Pos = InstrB(PosEnd,RequestBin,getByteString("Content-Type:"))
PosBeg = Pos+14
PosEnd = InstrB(PosBeg,RequestBin,getByteString(chr(13)))
@#Add content-type to dictionary object
ContentType = getString(MidB(RequestBin,PosBeg,PosEnd-PosBeg))
UploadControl.Add "ContentType",ContentType
@#Get content of object
PosBeg = PosEnd+4
PosEnd = InstrB(PosBeg,RequestBin,boundary)-2
Value = MidB(RequestBin,PosBeg,PosEnd-PosBeg)
Else
@#Get content of object
Pos = InstrB(Pos,RequestBin,getByteString(chr(13)))
PosBeg = Pos+4
PosEnd = InstrB(PosBeg,RequestBin,boundary)-2
Value = getString(MidB(RequestBin,PosBeg,PosEnd-PosBeg))
End If
@#Add content to dictionary object
UploadControl.Add "Value" , Value
@#Add dictionary object to main dictionary
UploadRequest.Add name, UploadControl
@#Loop to next object
BoundaryPos=InstrB(BoundaryPos+LenB(boundary),RequestBin,boundary)
Loop
End Sub
@#String to byte string conversion
Function getByteString(StringStr)
For i = 1 to Len(StringStr)
char = Mid(StringStr,i,1)
getByteString = getByteString & chrB(AscB(char))
Next
End Function
@#Byte string to string conversion
Function getString(StringBin)
getString =""
For intCount = 1 to LenB(StringBin)
getString = getString & chr(AscB(MidB(StringBin,intCount,1)))
Next
End Function
%>
test.mdb(dsn 名称:upload)
----------------------------------------
表pic:
id:自动加
filename:文本
type:文本
what:ole
-----------------------------------------
存成单个文件,放在一个目录下,打开(必须用http://...)getfile.htm
上传一个.gif或.jpg就可以显示了。
对于大文件在显示程序(showpic.asp)中可能会用到循环和getchunk方法。自己去做。记住,由于ASP目前暂时不支持二进行制读写,只能存二进制到数据库中。
有什么问题,请致电veryblue@chinese.com (IAmTrue)
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原文转自:http://www.ltesting.net