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实例详解ASP的上传功能
请诸位大虾能对其中的不正或不良这处予以指正。
我想循序渐进，先讲一个简单的，单个图片文件保存到数据库。
这个范例共包括三个ＡＳＰ文件和一个数据库（一个表），全部在同一目录下。
１、tblImage 表结构（ACCESS 2000）
sn 自动编号 序列号
content-type 文本 图片类型
image OLE 对象 图片数据
２、SimpleImageToData.asp：上传表单及保存图片到数据库的代码部分，主要文件。
<%@ Language=VBScript %>
<% option explicit %>
<%
‘’从一个完整路径中析出文件名称
function getFileNamefromPath(strPath)
getFileNamefromPath = mid(strPath,instrrev(strPath,"\")+1)
end function
‘’定义数据库连接字符串
dim cnstr
cnstr = "driver={Microsoft Aclearcase/" target="_blank" >ccess Driver (*.mdb)};dbq=" & server.MapPath("./upload.mdb")
%>
<HTML>
<HEAD>
<title>单个图像保存到数据库</title>
<meta http-equiv="Content-Type" content="text/html; charset=gb2312">
</HEAD>
<body>
<p><a href="SimpleImageToData.asp">上传图片</a>
<a href="ShowImageListFromData.asp">显示图片</a><hr></p>
<%
if request.ServerVariables("REQUEST_METHOD") = "POST" then
dim sCome, sGo, binData, strData
dim posB, posE, posSB, posSE
dim binCrlf
dim strPath, strFileName, strContentType
binCrlf = chrb(13)&chrb(10) ‘’定义一个单字节的回车换行符
set sCome = server.CreateObject("adodb.stream")
sCome.Type = 1 ‘’指定返回数据类型 adTypeBinary=1,adTypeText=2
sCome.Mode = 3 ‘’指定打开模式 adModeRead=1,adModeWrite=2,adModeReadWrite=3
sCome.Open
sCome.Write request.BinaryRead(request.TotalBytes)
sCome.Position = 0
binData = sCome.Read
‘’response.BinaryWrite binData ‘’调试用：显示提交的所有数据
‘’response.Write "<hr>" ‘’调试用
set sGo = server.CreateObject("adodb.stream")
sGo.Type = 1
sGo.Mode = 3
sGo.Open
posB = 1
posB = instrb(posB,binData,binCrlf)
posE = instrb(posB+1,binData,binCrlf)
‘’response.Write posB & " | " & posE & "<br>"
sCome.Position = posB+1
sCome.CopyTo sGo,posE-posB-2
sGo.Position = 0
sGo.Type = 2
sGo.Charset = "gb2312"
strData = sGo.ReadText
sGo.Close
‘’response.Write strData & "<hr>"
posSB = 1
posSB = instr(posSB,strData,"filename=""") + len("filename=""")
posSE = instr(posSB,strData,"""")
if posSE > posSB then
strPath = mid(strData,posSB,posSE-posSB)
‘’response.Write "本地路径：" & strPath & "<br>"
‘’response.Write "文件名：" & getFileNamefromPath(strPath) & "<br>"
posB = posE
posE = instrb(posB+1,binData,binCrlf)
‘’response.Write posB & " | " & posE & "<br>"
sGo.Type = 1
sGo.Mode = 3
sGo.Open
sCome.Position = posB
sCome.CopyTo sGo,posE-posB-1
sGo.Position = 0
sGo.Type = 2
sGo.Charset = "gb2312"
strData = sGo.ReadText
sGo.Close
strContentType = mid(strData,16) ‘’此处因为固定的，所以省略查找 :-)
‘’response.Write "图片类型：" & strContentType & "<hr>"
posB = posE+2
posE = instrb(posB+1,binData,binCrlf)
‘’response.Write posB & " | " & posE & "<br>"
sGo.Type = 1
sGo.Mode = 3
sGo.Open
sCome.Position = posB+1
sCome.CopyTo sGo,posE-posB-2
sGo.Position = 0
strData = sGo.Read
sGo.Close
‘’response.Write lenb(strData) & "<br>"
dim cn, rs, sql
set cn = server.CreateObject("adodb.connection")
cn.Open cnstr
set rs = server.CreateObject("adodb.recordset")
sql = "select * from tblImage"
rs.Open sql,cn,1,3
rs.AddNew
rs.Fields("content-type").Value = strContentType
rs.Fields("image").AppendChunk strData
rs.Update
rs.Close
set rs = nothing
cn.Close
set cn = nothing
response.Write "图片保存成功！" & "<br>"
else
response.Write "没有上传图片！" & "<br>"
end if
set sGo = nothing
sCome.Close
set sCome = nothing
else
%>
<form id="frmUpload" name="frmUpload" action="SimpleImageToData.asp" method="post" target="_self" enctype="multipart/form-data">
<INPUT id="filImage" type="file" name="filImage" size="40">
<BR>
<INPUT id="btnUpload" type="submit" value="Upload" name="btnUpload">
</form>
<%
end if
%>
</body>
</HTML>
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