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在asp中通过vbs类实现rsa加密与解密
发表于：2007-06-30来源：作者：点击数：
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本文章有两文件组成 test.asp 测试 演示文件 clsrsa.asp 实现rsa加密与解密的 vb s类文件 下面是代码: 1. test.asp % rem 文章标题:在asp中通过vbs类实现rsa加密与解密 rem 收集整理:yanek rem 联系:aspboy@263.net % %Option Explicit% !--#INCLUDE FILE=cls
本文章有两文件组成
test.asp 测试演示文件
clsrsa.asp 实现rsa加密与解密的vbs类文件
下面是代码:
1. test.asp
<%
rem 文章标题:在asp中通过vbs类实现rsa加密与解密
rem 收集整理:yanek
rem 联系:aspboy@263.net
%>
<%Option Explicit%>
<!--#INCLUDE FILE="clsRSA.asp"-->
<%
Dim LngKeyE
Dim LngKeyD
Dim LngKeyN
Dim StrMessage
Dim ObjRSA
If Not Request.Form = "" Then
LngKeyE = Request.Form("KeyE")
LngKeyD = Request.Form("KeyD")
LngKeyN = Request.Form("KeyN")
StrMessage = Request.Form("Message")
Set ObjRSA = New clsRSA
Select Case Request.Form("Action")
Case "Generate Keys"
Call ObjRSA.GenKey()
LngKeyE = ObjRSA.PublicKey
LngKeyD = ObjRSA.PrivateKey
LngKeyN = ObjRSA.Modulus
Case "Encrypt"
ObjRSA.PublicKey = LngKeyE
ObjRSA.Modulus = LngKeyN
StrMessage = ObjRSA.Encode(StrMessage)
Case "Decrypt"
ObjRSA.PrivateKey = LngKeyD
ObjRSA.Modulus = LngKeyN
StrMessage = ObjRSA.Decode(StrMessage)
End Select
Set ObjRSA = Nothing
End If
%>
<HTML>
<HEAD>
<TITLE>RSA Cipher Demonstration</TITLE>
</HEAD>
<BODY>
<H1>RSA Cipher Demonstration</H1>
<P>
You will first need to generate your public/privage key-pair
before you can encrypt/decrypt messages.
</P>
<FORM method="post">
<TABLE>
<TR>
<TD>Public Key</TD>
<TD><INPUT name="KeyE" value="<%=Server.HTMLEncode(LngKeyE)%>"></TD>
<TD rowspan="3">
<INPUT type="Submit" name="Action" value="Generate Keys">
</TD>
</TR>
<TR>
<TD>Private Key</TD>
<TD><INPUT name="KeyD" value="<%=Server.HTMLEncode(LngKeyD)%>"></TD>
</TR>
<TR>
<TD>Modulus</TD>
<TD><INPUT name="KeyN" value="<%=Server.HTMLEncode(LngKeyN)%>"></TD>
</TR>
<TR>
<TD colspan="3">
Test Message:<BR>
<TEXTAREA name="Message" cols="50" rows="7"><%=Server.HTMLEncode(StrMessage)%></TEXTAREA>
</TD>
</TR>
<TR>
<TD align="right" colspan="3">
<INPUT type="Submit" name="Action" value="Encrypt">
<INPUT type="Submit" name="Action" value="Decrypt">
</TD>
</TR>
</TABLE>
</FORM>
</BODY>
</HTML>
clsrsa.asp
<%
rem 实现rsa加密与解密的vbs类文件
rem 文章标题:在asp中通过vbs类实现rsa加密与解密
rem 收集整理:yanek
rem 联系:aspboy@263.net
‘’ RSA Encryption Class
‘’
‘’ .PrivateKey
‘’ Your personal private key. Keep this hidden.
‘’
‘’ .PublicKey
‘’ Key for others to encrypt data with.
‘’
‘’ .Modulus
‘’ Used with both public and private keys when encrypting
‘’ and decrypting data.
‘’
‘’ .GenKey()
‘’ Creates Public/Private key set and Modulus
‘’
‘’ .Crypt(pLngMessage, pLngKey)
‘’ Encrypts/Decrypts message and returns
‘’ as a string.
‘’
‘’ .Encode(pStrMessage)
‘’ Encrypts message and returns in double-hex format
‘’
‘’ .Decode(pStrMessage)
‘’ Decrypts message from double-hex format and returns a string
‘’
Class clsRSA
Public PrivateKey
Public PublicKey
Public Modulus
Public Sub GenKey()
Dim lLngPhi
Dim q
Dim p
Randomize
Do
Do
‘’ 2 random primary numbers (0 to 1000)
Do
p = Rnd * 1000 \ 1
Loop While Not IsPrime(p)
Do
q = Rnd * 1000 \ 1
Loop While Not IsPrime(q)
‘’ n = product of 2 primes
Modulus = p * q \ 1
‘’ random decryptor (2 to n)
PrivateKey = Rnd * (Modulus - 2) \ 1 + 2
lLngPhi = (p - 1) * (q - 1) \ 1
PublicKey = Euler(lLngPhi, PrivateKey)
Loop While PublicKey = 0 Or PublicKey = 1
‘’ Loop if we can‘’t crypt/decrypt a byte
Loop While Not TestCrypt(255)
End Sub
Private Function TestCrypt(ByRef pBytData)
Dim lStrCrypted
lStrCrypted = Crypt(pBytData, PublicKey)
TestCrypt = Crypt(lStrCrypted, PrivateKey) = pBytData
End Function
Private Function Euler(ByRef pLngPHI, ByRef pLngKey)
Dim lLngR(3)
Dim lLngP(3)
Dim lLngQ(3)
Dim lLngCounter
Dim lLngResult
Euler = 0
lLngR(1) = pLngPHI: lLngR(0) = pLngKey
lLngP(1) = 0: lLngP(0) = 1
lLngQ(1) = 2: lLngQ(0) = 0
lLngCounter = -1
Do Until lLngR(0) = 0
lLngR(2) = lLngR(1): lLngR(1) = lLngR(0)
lLngP(2) = lLngP(1): lLngP(1) = lLngP(0)
lLngQ(2) = lLngQ(1): lLngQ(1) = lLngQ(0)
lLngCounter = lLngCounter + 1
lLngR(0) = lLngR(2) Mod lLngR(1)
lLngP(0) = ((lLngR(2)\lLngR(1)) * lLngP(1)) + lLngP(2)
lLngQ(0) = ((lLngR(2)\lLngR(1)) * lLngQ(1)) + lLngQ(2)
Loop
lLngResult = (pLngKey * lLngP(1)) - (pLngPHI * lLngQ(1))
If lLngResult > 0 Then
Euler = lLngP(1)
Else
Euler = Abs(lLngP(1)) + pLngPHI
End If
End Function
Public Function Crypt(pLngMessage, pLngKey)
On Error Resume Next
Dim lLngMod
Dim lLngResult
Dim lLngIndex
If pLngKey Mod 2 = 0 Then
lLngResult = 1
For lLngIndex = 1 To pLngKey / 2
lLngMod = (pLngMessage ^ 2) Mod Modulus
‘’ Mod may error on key generation
lLngResult = (lLngMod * lLngResult) Mod Modulus
If Err Then Exit Function
Next
Else
lLngResult = pLngMessage
For lLngIndex = 1 To pLngKey / 2
lLngMod = (pLngMessage ^ 2) Mod Modulus
On Error Resume Next
‘’ Mod may error on key generation
lLngResult = (lLngMod * lLngResult) Mod Modulus
If Err Then Exit Function
Next
End If
Crypt = lLngResult
End Function
Private Function IsPrime(ByRef pLngNumber)
Dim lLngSquare
Dim lLngIndex
IsPrime = False
If pLngNumber < 2 Then Exit Function
If pLngNumber Mod 2 = 0 Then Exit Function
lLngSquare = Sqr(pLngNumber)
For lLngIndex = 3 To lLngSquare Step 2
If pLngNumber Mod lLngIndex = 0 Then Exit Function
Next
IsPrime = True
End Function
Public Function Encode(ByVal pStrMessage)
Dim lLngIndex
Dim lLngMaxIndex
Dim lBytAscii
Dim lLngEncrypted
lLngMaxIndex = Len(pStrMessage)
If lLngMaxIndex = 0 Then Exit Function
For lLngIndex = 1 To lLngMaxIndex
lBytAscii = Asc(Mid(pStrMessage, lLngIndex, 1))
lLngEncrypted = Crypt(lBytAscii, PublicKey)
Encode = Encode & NumberToHex(lLngEncrypted, 4)
Next
End Function
Public Function Decode(ByVal pStrMessage)
Dim lBytAscii
Dim lLngIndex
Dim lLngMaxIndex
Dim lLngEncryptedData
Decode = ""
lLngMaxIndex = Len(pStrMessage)
For lLngIndex = 1 To lLngMaxIndex Step 4
lLngEncryptedData = HexToNumber(Mid(pStrMessage, lLngIndex, 4))
lBytAscii = Crypt(lLngEncryptedData, PrivateKey)
Decode = Decode & Chr(lBytAscii)
Next
End Function
Private Function NumberToHex(ByRef pLngNumber, ByRef pLngLength)
NumberToHex = Right(String(pLngLength, "0") & Hex(pLngNumber), pLngLength)
End Function
Private Function HexToNumber(ByRef pStrHex)
HexToNumber = CLng("&h" & pStrHex)
End Function
End Class
%>
