oracle中如何编写树级代码

这是在2002年给一个制衣厂做系统的时候写的，请大家多批评指正！

create table Dept(
 DepartNO  varchar2(10),
   DepartName  varchar2(20),
 TopNo    varchar2(10));

insert into Dept values(@#001@#,@#懂事会@#,@#0@#);
insert into Dept values(@#002@#,@#总裁办@#,@#001@#);
insert into Dept values(@#003@#,@#财务部@#,@#001@#);
insert into Dept values(@#004@#,@#市场部@#,@#002@#);
insert into Dept values(@#005@#,@#公关部@#,@#002@#);
insert into Dept values(@#006@#,@#销售部@#,@#002@#);
insert into Dept values(@#007@#,@#分销处@#,@#006@#);
insert into Dept values(@#008@#,@#业务拓展处@#,@#004@#);
insert into Dept values(@#009@#,@#销售科@#,@#007@#);

CREATE TABLE TempDept
(
 TempdeptNo    char(4), /*部门编号*/
 TempdeptName   varchar2(20), /*部门名称*/
  UpperTempdeptNo  char(4), /*上级部门编号*/
  UpperTempdeptName  varchar2(20), /*上级部门名称*/
 TempdeptLevel   number(4) /*部门所处的级别*/
);

select departname
from dept
connect by prior departno=topno
start with topno=@#0@#;

select a.departname top ,b.departname next
from dept a,dept b
where a.departno=b.topno;

select lpad(departno,level*2+length(departno),@#\@#)
from dept
start with topno=@#0@#
connect by prior departno=topno;

select departno,departname,level ||@#\@#|| topno
from dept
start with topno=@#0@#
connect by prior departno=topno;

select lpad(departno,level*2+length(departno),@# @#)
from dept
start with topno=@#0@#
connect by prior departno=topno;

select lpad(departno,level*3,@# @#)
from dept
start with topno=@#0@#
connect by prior departno=topno;

create or replace function GetLevel(TempNo varchar2)
return varchar2
IS
 Result  varchar2(20);
 cursor CurLevel(curTempNo varchar2)
 is
 select departNo
 from dept
 connect by prior departNo = TopNo
 start with TopNo = curTempNo;
begin
 open CurLevel;
 for v_sor in CurLevel(TempNo) loop
   Result:=Result || @#/@# || v_sor.curTempNo;
 end loop;
 return(Result);
 close CurLevel;
  dbms_output.put_line(@#suclearcase/" target="_blank" >ccess@#);
end GetLevel;


REM************************************************************
REM**********   生成部门之间形成的树结构     ******************
REM********** 功能:输入部门后自动产生该部门  ******************
REM**********      及其子部门之间的树关系()  ******************
REM********** 输入参数：部门编号ParaDeptId   ******************
REM************************************************************

CREATE OR REPLACE procedure getAllSubDeptId(ParaDeptId varchar2)
IS
    DeptNo1       varchar2(4);     /*存放部门编号*/
    UpperDeptNo1  varchar2(4);     /*存放该部门的上级部门编号*/
    UpperDeptNo2  varchar2(4);     /*存放查询同级上级部门编号*/
    UpperDeptNo3  varchar2(4);     /*存放查询的上级部门编号*/
       level         number;          /*部门所处级别*/
    DSql          varchar2(100);   /*动态SQL字符串*/
    CURSOR getDept IS
       select DepartNO,TopNo
       from dept
       where DepartNo != ParaDeptId;
BEGIN
 --DSql :=@#create table tempdept(TempdeptNo,TempdeptName,UpperTempdeptNo,
  --UpperTempdeptName,TempdeptLevel)@#;
 --EXECUTE IMMEDIATE DSql;
   DSql :=@#TRUNCATE TABLE TempDept@#;
   dbms_output.put_line(0);
   EXECUTE IMMEDIATE DSql;
   dbms_output.put_line(1);
   insert into TempDept values(ParaDeptId,Null,Null,Null,0);
   dbms_output.put_line(2);
   open getDept;
   fetch getDept into DeptNo1,UpperDeptNo1;
   WHILE ( SQLCODE = 0 )
   LOOP
      level := 1 ;
      UpperDeptNo3 := UpperDeptNo1;
      WHILE ( UpperDeptNo1 is NOT NULL )
      loop
         if (UpperDeptNo1 = ParaDeptId) then
            insert into tempdept           values(DeptNo1,NULL,UpperDeptNo3,NULL,level);
           exit;
        else
           UpperDeptNo2 := UpperDeptNo1;
           select topNo into UpperDeptNo1
           from  dept
           where Departno= UpperDeptNo2;
           if UpperDeptNo2 != UpperDeptNo1
    then
                level := level+1;
           end if;
         end if;
      END LOOP;
     fetch getDept into DeptNo1,UpperDeptNo1;
   END LOOP;
   close getDept;
END;
/

原文转自：http://www.ltesting.net