SQL交叉表实例

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SQL交叉表实例

很简单的一个东西，见网上好多朋友问“怎么实现交叉表？”，以下是我写的一个例子，数据库基于SQL SERVER 2000。

-- ======================================================

--交叉表实例

-- ======================================================

建表：

在查询分析器里运行：

CREATE TABLE [Test] (

       [id] [int] IDENTITY (1, 1) NOT NULL ,

       [name] [nvarchar] (50) COLLATE Chinese_PRC_CI_AS NULL ,

       [subject] [nvarchar] (50) COLLATE Chinese_PRC_CI_AS NULL ,

       [Source] [numeric](18, 0) NULL

) ON [PRIMARY]

GO

INSERT INTO [test] ([name],[subject],[Source]) values (N@#张三@#,N@#语文@#,60)

INSERT INTO [test] ([name],[subject],[Source]) values (N@#李四@#,N@#数学@#,70)

INSERT INTO [test] ([name],[subject],[Source]) values (N@#王五@#,N@#英语@#,80)

INSERT INTO [test] ([name],[subject],[Source]) values (N@#王五@#,N@#数学@#,75)

INSERT INTO [test] ([name],[subject],[Source]) values (N@#王五@#,N@#语文@#,57)

INSERT INTO [test] ([name],[subject],[Source]) values (N@#李四@#,N@#语文@#,80)

INSERT INTO [test] ([name],[subject],[Source]) values (N@#张三@#,N@#英语@#,100)

Go

 

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交叉表语句的实现：

--用于：交叉表的列数是确定的

select name,sum(case subject when @#数学@# then source else 0 end) as @#数学@#,

          sum(case subject when @#英语@# then source else 0 end) as @#英语@#,

            sum(case subject when @#语文@# then source else 0 end) as @#语文@#

from test

group by name

 

 

--用于：交叉表的列数是不确定的

declare @sql varchar(8000)

set @sql = @#select name,@#

 

select @sql = @sql + @#sum(case subject when @#@#@#+subject+@#@#@#

                          then source else 0 end) as @#@#@#+subject+@#@#@#,@#

  from (select distinct subject from test) as a

 

select @sql = left(@sql,len(@sql)-1) + @# from test group by name@#

exec(@sql)

go

 

运行结果：

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原文转自：http://www.ltesting.net