T-SQL: 15 个与日期时间相关的自定义函数(UDF),周日作为周的最后一天,均不受 @@DateFirst、语言版
发表于:2007-07-02来源:作者:点击数:
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/* T-SQL: 15 个与日期时间相关的自定义函数(UDF),周日作为周的最后一天,均不受 @@DateFirst、语言版本影响 都是从老文章里收集或提炼出来的! 提示: (@@Datefirst + datepart(weekday,@Date)) % 7 判断周几是最保险的! 与 @@DateFirst 无关,与语言版本无关 @
/*
T-SQL: 15 个与日期时间相关的自定义函数(UDF),周日作为周的最后一天,均不受 @@DateFirst、语言版本影响
都是从老文章里收集或提炼出来的!
提示:
(@@Datefirst + datepart(weekday,@Date)) % 7 判断周几是最保险的! 与 @@DateFirst 无关,与语言版本无关
@@DateFirst 可能会导致 datepart(weekday,@Date) 不一样!
无论 @@DateFirst 等于几,无论是什么语言版本的 SQL Server 下面永远恒成立!
(@@Datefirst + datepart(weekday,@Date)): 2、3、4、5、6、0、1 分别代表 周一 到 周日
-- */
create function udf_GetAge(@StartDate datetime,@EndDate datetime)
returns integer
-- 返回精确年龄 select dbo.udf_GetAge(@#1949-10-01@#,ge
tdate())
begin
return datediff(year,@StartDate,@EndDate)
- case when datediff(day,dateadd(year,datediff(year,@StartDate,@EndDate),@StartDate),@EndDate) >= 0
then 0
else
1
end
end
go
create function udf_DaysOfYearByDate(@Date datetime)
RETURNS integer
-- 返回年的天数 可判断 平(365)、润(366) 年
begin
return datediff(day,dateadd(year,datediff(year,0,@Date),0),dateadd(year,datediff(year,0,@Date )+1,0))
end
go
create function udf_DaysOfYear(@Year integer)
RETURNS integer
-- 返回年的天数 可判断 平(365)、润(366) 年
begin
return datediff(day,dateadd(year,@year - year(0),0),dateadd(year,@year - year(0) + 1,0))
end
go
create function udf_HalfDay(@Date datetime)
returns datetime
-- 返回 @Date 是 上午 返回 @Date 的零点,@Date 是 下午 返回 @Date 的十二点
as
begin
return case when datepart(hour,@Date) < 12
then dateadd(day,datediff(day,0,@Date),0) --上午归到 零点
else
dateadd(hour,12,dateadd(day,datediff(day,0,@Date),0)) --下午归到 十二点
end
end
go
create function udf_WeekDiff(@StartDate datetime,@EndDate datetime)
returns integer
-- 返回 [@StartDate , @EndDate] 之间周数 周日是当周的最后一天
begin
return datediff(week,@StartDate,@EndDate) -- + 1
+ case when (@@Datefirst + datepart(weekday,@StartDate)) % 7 = 1
then 1
else
0
end
- case when (@@Datefirst + datepart(weekday,@EndDate)) % 7 = 1
then 1
else 0
end
end
go
create function udf_WeekOfMonth(@Date datetime)
-- 返回 @Date 是所在月的第几周 周日是当周的最后一天
returns integer
as
begin
return datediff(week
,case when (@@Datefirst + datepart(weekday,dateadd(month,datediff(month,0,@Date),0))) % 7 = 1
then dateadd(month,datediff(month,0,@Date),0) - 1
else
dateadd(month,datediff(month,0,@Date),0)
end
,case when (@@Datefirst + datepart(weekday,@Date)) % 7 = 1
then @Date-1
else @Date
end
) + 1
end
go
create function udf_WeekOfQuarter(@Date datetime)
-- 返回 @Date 是所在季度的第几周 周日是当周的最后一天
returns int
as
begin
return datediff(week
,case when (@@Datefirst + datepart(weekday,dateadd(Quarter,datediff(Quarter,0,@Date),0))) % 7 = 1
then dateadd(Quarter,datediff(Quarter,0,@Date),0) - 1
else
dateadd(Quarter,datediff(Quarter,0,@Date),0)
end
,case when (@@Datefirst + datepart(weekday,@Date)) % 7 = 1
then @Date - 1
else
@Date
end
) + 1
end
go
create function udf_WeekOfYear(@Date datetime)
-- 返回 @Date 是所在年的第几周 周日是当周的最后一天
returns int
as
begin
return datediff(week
,case when (@@Datefirst + datepart(weekday,dateadd(day,0,datediff(day,0,dateadd(year,datediff(year,0,@Date),0))))) % 7 = 1
then dateadd(day,-1,dateadd(day,0,datediff(day,0,dateadd(year,datediff(year,0,@Date),0))))
else
dateadd(day,0,datediff(day,0,dateadd(year,datediff(year,0,@Date),0))) --date 所在年的第一天 即: 一月一号
end
,case when (@@Datefirst + datepart(weekday,@Date)) % 7 = 1
then dateadd(day,-1,@Date)
else
@Date
end
) + 1
end
go
create function udf_WeekDay(@ int,@Date datetime)
returns datetime
-- 返回 @Date 映射到 所在周的其他天 周日是当周的最后一天
begin
/*
--周日算作(上一)周的最后一天
当 @ <= 1 代表将 @Date 映射到 所在周的星期一
当 @ = 2 代表将 @Date 映射到 所在周的星期二
当 @ = 3 代表将 @Date 映射到 所在周的星期三
当 @ = 4 代表将 @Date 映射到 所在周的星期四
当 @ = 5 代表将 @Date 映射到 所在周的星期五
当 @ = 6 代表将 @Date 映射到 所在周的星期六
当 @ >= 7 代表将 @Date 映射到 所在周的星期日
可用于按周汇总 Group by,均支持跨年跨月数据
*/
return dateadd(day
,case when (@@Datefirst + datepart(weekday,@Date)) % 7 = 0 --周六
then case when @ between 1 and 6
then @ - 6
else
1
end
when (@@Datefirst + datepart(weekday,@Date)) % 7 = 1 --周日(七)
then case when @ between 1 and 6
then @ - 7
else
0
end
when (@@Datefirst + datepart(weekday,@Date)) % 7 between 2 and 6 --周一至周五
then case when @ between 1 and 6
then @ + 1 - (@@Datefirst + datepart(weekday,@Date)) % 7
else
8 - (@@Datefirst + datepart(weekday,@Date)) % 7
end
end
,@Date)
end
go
create function udf_WeekdayDiff(@Weekday integer,@StartDate datetime,@EndDate datetime)
returns integer
-- -- 返回 [@StartDate , @EndDate] 之间周一 到 周日的个数 周日是当周的最后一天
begin
-- @Weekday: 1: Monday , ... ,7: Sunday
return datediff(week,@StartDate,@EndDate)
+ case when (@@Datefirst + datepart(weekday,@StartDate)) % 7
+ case when (@@Datefirst + datepart(weekday,@StartDate)) % 7 = 0
then 7
else
0
end > @Weekday % 7 + 1
then 0
else 1
end
- case when (@@Datefirst + datepart(weekday,@EndDate)) % 7
+ case when (@@Datefirst + datepart(weekday,@EndDate)) % 7 = 0
then 7
else 0
end >= @Weekday % 7 + 1
then
0
else
1
end
/* test:
declare @b datetime
declare @e datetime
set @b = @#2004-01-29@#
set @e = @#2004-09-05@#
select @b as BeginDate ,@e as EndDate
,dbo.udf_WeekdayDiff(1,@b,@e) as CountOfMonday
,dbo.udf_WeekdayDiff(2,@b,@e) as CountOfTuesday
,dbo.udf_WeekdayDiff(3,@b,@e) as CountOfWednesday
,dbo.udf_WeekdayDiff(4,@b,@e) as CountOfThursday
,dbo.udf_WeekdayDiff(5,@b,@e) as CountOfFriday
,dbo.udf_WeekdayDiff(6,@b,@e) as CountOfSaturday
,dbo.udf_WeekdayDiff(7,@b,@e) as CountOfSunday
*/
end
go
create function udf_WeekdayID(@Date datetime)
returns integer
-- 返回 @Date 是 Monday 返回 1, ... ,是 Sunday 返回 1
begin
--1: Monday , ... ,7: Sunday
return (@@Datefirst + datepart(weekday,@Date)) % 7
+ case when (@@Datefirst + datepart(weekday,@Date)) % 7 < 2
then 6
else
-1
end
end
go
create function udf_NextWorkDate(@Date datetime)
returns datetime
-- 返回 @Date 的下一个工作日
begin
/*
declare @i int
set @i = 3
declare @Date datetime
set @Date = @#2005-01-02@#
-- */
return case when (@@Datefirst + datepart(weekday,@Date)) % 7 = 6 -- Friday
then dateadd(day,3,@Date)
when (@@Datefirst + datepart(weekday,@Date)) % 7 = 0 -- saturday
then dateadd(day,2,@Date)
else
dateadd(day,1,@Date)
end
end
go
create function udf_PreviousWorkDate(@Date datetime)
returns datetime
-- 返回 @Date 的上一个工作日
begin
/*
declare @i int
set @i = 3
declare @Date datetime
set @Date = @#2005-01-02@#
-- */
return case when (@@Datefirst + datepart(weekday,@Date)) % 7 = 2 -- Monday
then dateadd(day,-3,@Date)
when (@@Datefirst + datepart(weekday,@Date)) % 7 = 1 -- Sunday
then dateadd(day,-2,@Date)
else
dateadd(day,-1,@Date)
end
end
go
create function udf_WorkDateAdd(@i integer,@Date datetime)
returns datetime
-- 返回 @Date 加上一段 @i 个工作日的新值
begin
declare @ int
set @ = 0
while @ < abs(@i)
begin
set @Date = case when @i >= 0
then --dbo.udf_nextworkdate(@Date)
case when (@@Datefirst + datepart(weekday,@Date)) % 7 = 6 -- Friday
then dateadd(day,3,@Date)
when (@@Datefirst + datepart(weekday,@Date)) % 7 = 0 -- saturday
then dateadd(day,2,@Date)
else
dateadd(day,1,@Date)
end
else
--dbo.udf_previousworkdate(@Date)
case when (@@Datefirst + datepart(weekday,@Date)) % 7 = 2 -- Monday
then dateadd(day,-3,@Date)
when (@@Datefirst + datepart(weekday,@Date)) % 7 = 1 -- Sunday
then dateadd(day,-2,@Date)
else
dateadd(day,-1,@Date)
end
end
set @ = @ + 1
end
return @Date
end
go
create function udf_GetStar (@ datetime)
RETURNS varchar(100)
-- 返回日期所属星座
BEGIN
RETURN
(
--declare @ datetime
--set @ = getdate()
select max(star)
from
(
select @#魔羯座@# as star,1 as [month],1 as [day]
union all select @#水瓶座@#,1,20
union all select @#双鱼座@#,2,19
union all select @#牡羊座@#,3,21
union all select @#金牛座@#,4,20
union all select @#双子座@#,5,21
union all select @#巨蟹座@#,6,22
union all select @#狮子座@#,7,23
union all select @#处女座@#,8,23
union all select @#天秤座@#,9,23
union all select @#天蝎座@#,10,24
union all select @#射手座@#,11,22
union all select @#魔羯座@#,12,22
) stars
where dateadd(month,[month] - 1,dateadd(year,year(@) - year(0),0)) + [day] - 1 =
(
select max(dateadd(month,[month] - 1,dateadd(year,year(@) - year(0),0)) + [day] - 1)
from (
select @#魔羯座@# as star,1 as [month],1 as [day]
union all select @#水瓶座@#,1,20
union all select @#双鱼座@#,2,19
union all select @#牡羊座@#,3,21
union all select @#金牛座@#,4,20
union all select @#双子座@#,5,21
union all select @#巨蟹座@#,6,22
union all select @#狮子座@#,7,23
union all select @#处女座@#,8,23
union all select @#天秤座@#,9,23
union all select @#天蝎座@#,10,24
union all select @#射手座@#,11,22
union all select @#魔羯座@#,12,22
) stars
where @ >= dateadd(month,[month] - 1,dateadd(year,year(@) - year(0),0)) + [day] - 1
)
)
end
原文转自:http://www.ltesting.net