让数据库产生一张详细的日历表

发表于:2007-07-02来源:作者:点击数: 标签:
让数据库产生一张详细的日历表 也许有了这张表,你的工作会轻松很多! CREATE TABLE [dbo].[time_dimension] ( [time_id] [int] IDENTITY (1, 1) NOT NULL , [the_date] [datetime] NULL , [the_day] [nvarchar] (15) NULL , [the_month] [nvarchar] (15) NU

让数据库产生一张详细的日历表

也许有了这张表,你的工作会轻松很多!

CREATE TABLE [dbo].[time_dimension] (
   [time_id] [int] IDENTITY (1, 1) NOT NULL ,
   [the_date] [datetime] NULL ,
   [the_day] [nvarchar] (15) NULL ,
   [the_month] [nvarchar] (15) NULL ,
   [the_year] [smallint] NULL ,
   [day_of_month] [smallint] NULL ,
   [week_of_year] [smallint] NULL ,
   [month_of_year] [smallint] NULL ,
   [quarter] [nvarchar] (2) NULL ,
   [fiscal_period] [nvarchar] (20) NULL
) ON [PRIMARY]

 
DECLARE @WeekString varchar(12),
@dDate SMALLDATETIME,
@sMonth varchar(20),
@iYear smallint,
@iDayOfMonth smallint,
@iWeekOfYear smallint,
@iMonthOfYear smallint,
@sQuarter varchar(2),
@sSQL varchar(100),
@adddays int
 
SELECT @adddays = 1 --日期增量(可以自由设定)
SELECT @dDate = @#01/01/2002@# --开始日期
 
WHILE @dDate < @#12/31/2004@#  --结束日期
BEGIN
 
   SELECT @WeekString = DATENAME (dw, @dDate)
   SELECT @sMonth=DATENAME(mm,@dDate)
   SELECT @iYear= DATENAME (yy, @dDate)
   SELECT @iDayOfMonth=DATENAME (dd, @dDate)
   SELECT @iWeekOfYear= DATENAME (week, @dDate)
   SELECT @iMonthOfYear=DATEPART(month, @dDate)
   SELECT @sQuarter = @#Q@# +  CAST(DATENAME (quarter, @dDate)as varchar(1))

   INSERT INTO time_dimension(the_date, the_day, the_month, the_year,
   day_of_month,
   week_of_year, month_of_year, quarter) VALUES
   (@dDate, @WeekString, @sMonth, @iYear, @iDayOfMonth, @iWeekOfYear,
   @iMonthOfYear, @sQuarter)
   SELECT @dDate = @dDate + @adddays
END
GO

select * from time_dimension

原文转自:http://www.ltesting.net