如何取得MSSQL中的存储过程的返回值

声明存储过程
CREATE PROCEDURE sp_results_demo @InParmInt Int,@OutParmInt OUTPUT
AS
BEGIN
SELECT 1,2,3,4
SELECT uid,id
FROM sysobjects
WHERE type=@#U@#

SELECT @OutParmInt=69

Return 16
END
用于返回每个返回值时用PowerScrip如下：
Long lReturn,lPram1,lPram2,lResult1,lResult2,lResult3,lResult4,lResult5,lResult6

DECLARE results_demo PROCEDURE FOR
@returnValue=sp_results_demo
@InParmInt = :lPram1,
@OutParmInt = :lPram2 OUTPUT using sqlca;

execute results_demo;

Do While SQLCA.SQLCode=0
Fetch results_demo INTO :lResult1,:lResult2,:lResult3,:lResult4 ;
Loop

Fetch results_demo INTO :lResult5,:lResult6 ;

Do While sqlca.sqlcode=0
Fetch results_demo Into :lResult5,:lResult6;
Loop

Fetch results_demo Into :lReturn,:lPram2;

Close results_demo ;


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原文转自：http://www.ltesting.net