在不破坏原加密存储过程的前提下,解密存储过程!(补充j9988)

实为 转贴j9988+原创

begin transaction  --playyuer 原创
exec sp_decrypt @#AppSP_test@# --j9988 原创
rollback transaction --playyuer 原创

or:或者直接用 transaction 把 j9988 包起来!
begin transaction
j9988
rollback transaction

/************* 解密存储过程 **********
------------------------sql2000大于40000的-----------------
原作：j9988 号:J老师
*/
alter  PROCEDURE sp_decrypt (@objectName varchar(50))
AS
begin

begin transaction --add by playyuer

declare @objectname1 varchar(100)
declare @sql1 nvarchar(4000),@sql2 nvarchar(4000),@sql3 nvarchar(4000),@sql4 nvarchar(4000),@sql5 nvarchar(4000),@sql6 nvarchar(4000),@sql7 nvarchar(4000),@sql8 nvarchar(4000),@sql9 nvarchar(4000),@sql10 nvarchar(4000) 
DECLARE  @OrigSpText1 nvarchar(4000),  @OrigSpText2 nvarchar(4000) , @OrigSpText3 nvarchar(4000), @resultsp nvarchar(4000)
declare  @i int , @t bigint
declare @m int,@n int,@q int
set @m=(SELECT max(colid) FROM syscomments  WHERE id = object_id(@objectName))
set @n=1
--get encrypted data
create table  #temp(colid int,ctext varbinary(8000))
insert #temp SELECT colid,ctext FROM syscomments  WHERE id = object_id(@objectName)
set @sql1=@#ALTER PROCEDURE @#+ @objectName +@# WITH ENCRYPTION AS @#
--set @sql1=@#ALTER PROCEDURE @#+ @objectName +@# WITH ENCRYPTION AS @#
set @q=len(@sql1)
set @sql1=@sql1+REPLICATE(@#-@#,4000-@q)
select @sql2=REPLICATE(@#-@#,4000),@sql3=REPLICATE(@#-@#,4000),@sql4=REPLICATE(@#-@#,4000),@sql5=REPLICATE(@#-@#,4000),@sql6=REPLICATE(@#-@#,4000),@sql7=REPLICATE(@#-@#,4000),@sql8=REPLICATE(@#-@#,4000),@sql9=REPLICATE(@#-@#,4000),@sql10=REPLICATE(@#-@#,4000)
exec(@sql1+@sql2+@sql3+@sql4+@sql5+@sql6+@sql7+@sql8+@sql9+@sql10)
while @n<=@m
begin
SET @OrigSpText1=(SELECT ctext FROM #temp  WHERE colid=@n)
set @objectname1=@objectname+@#_t@#
SET @OrigSpText3=(SELECT ctext FROM syscomments WHERE id=object_id(@objectName) and colid=@n)
if @n=1
begin
SET @OrigSpText2=@#CREATE PROCEDURE @#+ @objectName +@# WITH ENCRYPTION AS @#--
set @q=4000-len(@OrigSpText2)
set @OrigSpText2=@OrigSpText2+REPLICATE(@#-@#,@q)
end
else
begin
SET @OrigSpText2=REPLICATE(@#-@#, 4000)
end
--start counter
SET @i=1
--fill temporary variable
SET @resultsp = replicate(N@#A@#, (datalength(@OrigSpText1) / 2))

--loop
WHILE @i<=datalength(@OrigSpText1)/2
BEGIN
--reverse encryption (XOR original+bogus+bogus encrypted)
SET @resultsp = stuff(@resultsp, @i, 1, NCHAR(UNICODE(substring(@OrigSpText1, @i, 1)) ^
                                (UNICODE(substring(@OrigSpText2, @i, 1)) ^
                                UNICODE(substring(@OrigSpText3, @i, 1)))))
    SET @i=@i+1
END
--drop original SP
--EXECUTE (@#drop PROCEDURE @#+ @objectName)
--remove encryption
--preserve case
SET @resultsp=REPLACE((@resultsp),@#WITH ENCRYPTION@#, @#@#)
SET @resultsp=REPLACE((@resultsp),@#With Encryption@#, @#@#)
SET @resultsp=REPLACE((@resultsp),@#with encryption@#, @#@#)
IF CHARINDEX(@#WITH ENCRYPTION@#,UPPER(@resultsp) )>0
  SET @resultsp=REPLACE(UPPER(@resultsp),@#WITH ENCRYPTION@#, @#@#)
--replace Stored procedure without enryption
print @resultsp
--execute( @resultsp)
set @n=@n+1
end
drop table #temp
end
rollback transaction --add by playyuer
GO

/*
适合40000字符。
每次4000　print出来，自已贴。
切记：我见过的解过程都是对原过程进行破坏。破解前一定要备份!!!!
超过40000的，自已加SQL（我上面用SQL.SQL2－－SQL10）
超长的可加SQL11--sql20........
*/


 

原文转自：http://www.ltesting.net