一个在PHP中利用递归实现论坛分级显示的例子(为了简单起见,我将分页显示部分去掉了)
发表于:2007-07-01来源:作者:点击数:
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? php /*存放帖子的表结构 CREATE TABLE announce ( announce_id int(11) NOT NULL auto_increment, board_id smallint(6) NOT NULL, title varchar(100) NOT NULL, content tinytext, add_time datetime DEFAULT @#0000-00-00 00:00:00@# NOT NULL, auth_nam
<?
php
/*存放帖子的表结构
CREATE TABLE announce (
announce_id int(11) NOT NULL auto_increment,
board_id smallint(6) NOT NULL,
title varchar(100) NOT NULL,
content tinytext,
add_time datetime DEFAULT @#0000-00-00 00:00:00@# NOT NULL,
auth_name varchar(20) NOT NULL,
auth_mail varchar(40),
hit_count smallint(6) NOT NULL,
bytes mediumint(9) NOT NULL,
parent_id tinyint(4) NOT NULL,
auth_ip varchar(15) NOT NULL,
top_id int(11) NOT NULL,
return_count tinyint(4) NOT NULL,
face char(3) NOT NULL,
PRIMARY KEY (announce_id),
KEY board_id (board_id),
KEY top_id (top_id)
);
*/
function show_announce($id,$self_id){
global $dbconnect;
global $board_id;
$query="select * from announce where announce_id=@#$id@#";
$result=
mysql_query($query,$dbconnect);
$myrow=mysql_fetch_array($result);
mysql_free_result($result);
echo "<li>\n";
echo "<img src=@#images/mood".$myrow[face].".gif@#> ";
if($self_id!=$id)
echo "<a href=@#show.php3?board_id=$board_id&announce_id=$myrow[announce_id]&top_id=$myrow[top_id]@#>";
echo $myrow[title];
if($self_id!=$id)
echo "</a>";
echo " - <strong>【".$myrow[auth_name]."】</strong> ".$myrow[add_time]." <font color=darkblue>[id:$myrow][announce_id] 点击:$myrow[hit_count]]</font> ($myrow[bytes] Bytes) <font color=red>($myrow[return_count])</font>\n";
$query="select announce_id from announce where parent_id=@#$id@# order by announce_id desc";
$result=mysql_query($query,$dbconnect);
echo "<ul>\n";
while($myrow=mysql_fetch_array($result)){
show_announce($myrow[announce_id],$self_id);
}
echo "</ul>\n";
mysql_free_result($result);
echo "</li>";
}
?>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=gb2312">
<title>
论坛内容</title>
<link rel="stylesheet" type="text/css" href="common.css">
</head>
<body>
<?php
//此处需要连接
数据库
//可以根据需要加入分页
$query="select announce_id from announce where top_id=@#0@# order by announce_id desc ";
$result_top=mysql_query($query,$dbconnect);
echo "<ul>\n";
while($myrow_top=mysql_fetch_array($result_top)){
show_announce($myrow_top[announce_id],0);
}
echo "</ul>\n";
mysql_free_result($result_top);
?>
</body>
</html>
原文转自:http://www.ltesting.net