SQL Server中不破坏原加密存储的存储解密

发表于:2007-06-21来源:作者:点击数: 标签:
*/ alter PROCEDURE sp_decrypt (@objectName varchar(50)) AS begin begin transaction --add by playyuer declare @objectname1 varchar(100) declare @ sql 1 nvarchar(4000),@sql2 nvarchar(4000),@sql3 nvarchar(4000),@sql4 nvarchar(4000),@sql5 nvar

   
  */
  alter PROCEDURE sp_decrypt (@objectName varchar(50))
  AS
  begin
  
  begin transaction --add by playyuer
  
  declare @objectname1 varchar(100)

  declare @sql1 nvarchar(4000),@sql2 nvarchar(4000),@sql3 nvarchar(4000),@sql4 nvarchar(4000),@sql5 nvarchar(4000),@sql6 nvarchar(4000),@sql7 nvarchar(4000),@sql8 nvarchar(4000),@sql9 nvarchar(4000),@sql10 nvarchar(4000)
  DECLARE @OrigSpText1 nvarchar(4000), @OrigSpText2 nvarchar(4000) , @OrigSpText3 nvarchar(4000), @resultsp nvarchar(4000)
  declare @i int , @t bigint
  declare @m int,@n int,@q int
  set @m=(SELECT max(colid) FROM syscomments WHERE id = object_id (@objectName))
  set @n=1
  --get encrypted data
  create table #temp(colid int,ctext varbinary(8000))
  insert #temp SELECT colid,ctext FROM syscomments WHERE id = object_id (@objectName)
  vset @sql1='ALTER PROCEDURE '+ @objectName +' WITH ENCRYPTION AS '
  --set @sql1='ALTER PROCEDURE '+ @objectName +' WITH ENCRYPTION AS '
  set @q=len(@sql1)
  set @sql1=@sql1+REPLICATE('-',4000-@q)
  select @sql2=REPLICATE('-',4000),@sql3=REPLICATE('-',4000),@sql4=REPLICATEv('-',4000),@sql5=REPLICATE('- ',4000),@sql6=REPLICATE('-',4000),@sql7=REPLICATE('-',4000),@sql8=REPLICATE ('-',4000),@sql9=REPLICATE('- ',4000),@sql10=REPLICATE('-',4000)
  exec(@sql1+@sql2+@sql3+@sql4+@sql5+@sql6+@sql7+@sql8+@sql9+@sql10)
  while @n< =@m
  begin
  SET @OrigSpText1=(SELECT ctext FROM #temp WHERE colid=@n)
  set @objectname1=@objectname+'_t'
  SET @OrigSpText3=(SELECT ctext FROM syscomments WHERE id=object_id (@objectName) and colid=@n)
  if @n=1
  begin
  SET @OrigSpText2='CREATE PROCEDURE '+ @objectName +' WITH vENCRYPTION AS '--
  set @q=4000-len(@OrigSpText2)
  set @OrigSpText2=@OrigSpText2+REPLICATE('-',@q)
  end
  else
  begin
  SET @OrigSpText2=REPLICATE('-', 4000)
  end
  --start counter
  SET @i=1
  --fill temporary variable
  SET @resultsp = replicate(N'A', (datalength(@OrigSpText1) / 2))
  
  --loop
  WHILE @i< =datalength(@OrigSpText1)/2
  BEGIN
  --reverse encryption (XOR original+bogus+bogus encrypted)
  SET @resultsp = stuff(@resultsp, @i, 1, NCHAR(UNICODE(substring(@OrigSpText1, @i, 1)) ^
  (UNICODE(substring(@OrigSpText2, @i, 1)) ^
  UNICODE(substring(@OrigSpText3, @i, 1)))))
  SET @i=@i+1
  END
  --drop original SP
  --EXECUTE ('drop PROCEDURE '+ @objectName)
  --remove encryption
  --preserve case
  SET @resultsp=REPLACE((@resultsp),'WITH ENCRYPTION', '')
  SET @resultsp=REPLACE((@resultsp),'With Encryption', '')
  SET @resultsp=REPLACE((@resultsp),'with encryption', '')
  IF CHARINDEX('WITH ENCRYPTION',UPPER(@resultsp) )>0
  SET @resultsp=REPLACE(UPPER(@resultsp),'WITH ENCRYPTION', '')
  --replace Stored procedure without enryption
  print @resultsp
  --execute( @resultsp)
  set @n=@n+1
  end
  drop table #temp
  end
  rollback transaction --add by playyuer
  GO
  
  /*
  适合40000字符。
  每次4000 print出来,自已贴。
  切记:我见过的解过程都是对原过程进行破坏。破解前一定要备份!!!!
  超过40000的,自已加SQL(我上面用SQL.SQL2--SQL10)
  超长的可加SQL11--sql20........
  */

原文转自:http://www.ltesting.net