网络填表终结者破解分析

发表于:2007-05-25来源:作者:点击数: 标签:分析网络填表终结者破解
下载地址: http://www.onlinedown.net/soft/8912.htm" ------------------------------------------------------------ 破解工具: w32Dasm OLLYDBG 破解目的: 学习~~~ ------------------------------------------------------------ [破解过程] 用户输入

 
下载地址:

http://www.onlinedown.net/soft/8912.htm"
------------------------------------------------------------
破解工具:
w32Dasm OLLYDBG  
破解目的:
学习~~~
------------------------------------------------------------
  
[破解过程]
用户输入:冷枫
假注册码:52225229
  
详细过程:
004ACA52  |. 55             PUSH EBP
004ACA53  |. 68 25CD4A00    PUSH 1.004ACD25
004ACA58  |. 64:FF30        PUSH DWORD PTR FS:[EAX]
004ACA5B  |. 64:8920        MOV DWORD PTR FS:[EAX],ESP
004ACA5E  |. 8D55 FC        LEA EDX,DWORD PTR SS:[EBP-4]
004ACA61  |. 8B83 F4020000  MOV EAX,DWORD PTR DS:[EBX+2F4]
004ACA67  |. E8 BC40F9FF    CALL 1.00440B28   
  ↑__//取用户名的位数~~~~~
004ACA6C  |. 837 FC 00     CMP DWORD PTR SS:[EBP-4],0
↑__//比较是否输入~~eax=4   输入跳走去,不输入弹出提示~~~~~
004A70  |. 75 29          JNZ SHORT 1.004ACA9B
004ACA72  |. 68 30100000    PUSH 1030                                
004ACA77  |. 68 34CD4A00    PUSH 1.004ACD34                          
004ACA7C  |. 68 3CCD4A00    PUSH 1.004ACD3C                          
004ACA81  |. 6A 00          PUSH 0                                   
004ACA83  |. E8 B0ABF5FF    CALL <JMP.&user32.MessageBoxA>           
004ACA88  |. 8B83 F4020000  MOV EAX,DWORD PTR DS:[EBX+2F4]
004ACA8E  |. 8B10           MOV EDX,DWORD PTR DS:[EAX]
004ACA90  |. FF92 C0000000  CALL DWORD PTR DS:[EDX+C0]
004ACA96  |. E9 3A020000    JMP 1.004ACCD5
↓--从上面到这,来比较注册码位数
004ACA9B  |> 8D55 F8        LEA EDX,DWORD PTR SS:[EBP-8]
004ACA9E  |. 8B83 F8020000  MOV EAX,DWORD PTR DS:[EBX+2F8]
004ACAA4  |. E8 7F40F9FF    CALL 1.00440B28
↑__//取注册码的位数~~~~~
004ACAA9  |. 837D F8 00     CMP DWORD PTR SS:[EBP-8],0
↑__//比较是否输入~~eax=4   输入跳走去,不输入弹出提示~~
004ACAAD  |. 75 29          JNZ SHORT 1.004ACAD8
004ACAAF  |. 68 30100000    PUSH 1030                              
004ACAB4  |. 68 34CD4A00    PUSH 1.004ACD34                          
004ACAB9  |. 68 4CCD4A00    PUSH 1.004ACD4C                         
004ACABE  |. 6A 00          PUSH 0                                  
004ACAC0  |. E8 73ABF5FF    CALL <JMP.&user32.MessageBoxA>          
004ACAC5  |. 8B83 F8020000  MOV EAX,DWORD PTR DS:[EBX+2F8]
004ACACB  |. 8B10           MOV EDX,DWORD PTR DS:[EAX]
004ACACD  |. FF92 C0000000  CALL DWORD PTR DS:[EDX+C0]
004ACAD3  |. E9 FD010000    JMP 1.004ACCD5
↓--从上面到这,哈哈,终于来到要点了~~~睁大眼球哦
004ACAD8  |> 8D45 F0        LEA EAX,DWORD PTR SS:[EBP-10]
004ACADB  |. 50             PUSH EAX
004ACADC  |. 8D55 EC        LEA EDX,DWORD PTR SS:[EBP-14]
004ACADF  |. 8B83 FC020000  MOV EAX,DWORD PTR DS:[EBX+2FC]
004ACAE5  |. E8 3E40F9FF    CALL 1.00440B28
↑__//取机器码位数 0A  [我的机器码1439138432]
004ACAEA  |. 8B45 EC        MOV EAX,DWORD PTR SS:[EBP-14]
↑__// 将机器码1439138432移到---eax
004ACAED  |. B9 08000000    MOV ECX,8
↑__//将8移到ecx  
[从后面跟踪发现,是取机器码前8位,有时跟不懂,慢慢跟几次就会好了]
004ACAF2  |. BA 01000000    MOV EDX,1
↑__//将8移到edx 应该是从机器码第一位开始取吧~~
004ACAF7  |. E8 1C81F5FF    CALL 1.00404C18
↑__//取机器码前8位到14391384----eax
004ACAFC  |. 8B45 F0        MOV EAX,DWORD PTR SS:[EBP-10]
004ACAFF  |. E8 44C4F5FF    CALL 1.00408F48
↑__//将机器码前8位的16进制[DB9858]到eax
004ACB04  |. 8BF0           MOV ESI,EAX
↑__// 将eax16进制[DB9858]到esi
004ACB06  |. 8D55 E8        LEA EDX,DWORD PTR SS:[EBP-18]
004ACB09  |. 8B83 F4020000  MOV EAX,DWORD PTR DS:[EBX+2F4]
004ACB0F  |. E8 1440F9FF    CALL 1.00440B28
↑__//取用户的位数[4]
004ACB14  |. 8B45 E8        MOV EAX,DWORD PTR SS:[EBP-18]
004ACB17  |. E8 A47EF5FF    CALL 1.004049C0
004ACB1C  |. 0FAFF0         IMUL ESI,EAX
↑__//用机器码前8位16进制乘用户位数=DB9858*4=36e6160  
004ACB1F  |. 8BC6           MOV EAX,ESI
↑__//36e6160 --->eax
004ACB21  |. 05 41C20B00    ADD EAX,0BC241
↑__// eax[36e6160 ] ADD 0BC241= 37A23A1  --->真正注册码
004ACB26  |. 8D4D F4        LEA ECX,DWORD PTR SS:[EBP-C]
004ACB29  |. 33D2           XOR EDX,EDX
004ACB2B  |. E8 DCC3F5FF    CALL 1.00408F0C
004ACB30  |. 8B45 F4        MOV EAX,DWORD PTR SS:[EBP-C]
004ACB33  |. 50             PUSH EAX
004ACB34  |. 8D55 E4        LEA EDX,DWORD PTR SS:[EBP-1C]
↑__//将真注册码到eax[37A23A1]
004ACB37  |. 8B83 F8020000  MOV EAX,DWORD PTR DS:[EBX+2F8]
004ACB3D  |. E8 E63FF9FF    CALL 1.00440B28
004ACB42  |. 8B55 E4        MOV EDX,DWORD PTR SS:[EBP-1C]
↑__//我们输入的注册码[52225229]
004ACB45  |. 58             POP EAX
004ACB46  |. E8 B97FF5FF    CALL 1.00404B04
↑__//比较真假注册码的地方
004ACB4B  |. 0F85 60010000  JNZ 1.004ACCB1
↑__//关键跳转,不跳则OK,跳则OVER

最后得:
冷枫
37A23A1
  
破解小结:
算法总结:
取机器码前8位,和用户位数,然后用前8位16进制和用户位数相乘,再ADD  0BC241 就得注册码。

原文转自:http://www.ltesting.net