SQL交叉表实例
很简单的一个东西，见网上好多朋友问“怎么实现交叉表？”，以下是我写的一个例子，数据库基于SQL SERVER 2000。
-- ======================================================
--交叉表实例
-- ======================================================
建表：
在查询分析器里运行：
CREATE TABLE [Test] (
[id] [int] IDENTITY (1, 1) NOT NULL ,
[name] [nvarchar] (50) COLLATE Chinese_PRC_CI_AS NULL ,
[subject] [nvarchar] (50) COLLATE Chinese_PRC_CI_AS NULL ,
[Source] [numeric](18, 0) NULL
) ON [PRIMARY]
GO
INSERT INTO [test] ([name],[subject],[Source]) values (N@#张三@#,N@#语文@#,60)
INSERT INTO [test] ([name],[subject],[Source]) values (N@#李四@#,N@#数学@#,70)
INSERT INTO [test] ([name],[subject],[Source]) values (N@#王五@#,N@#英语@#,80)
INSERT INTO [test] ([name],[subject],[Source]) values (N@#王五@#,N@#数学@#,75)
INSERT INTO [test] ([name],[subject],[Source]) values (N@#王五@#,N@#语文@#,57)
INSERT INTO [test] ([name],[subject],[Source]) values (N@#李四@#,N@#语文@#,80)
INSERT INTO [test] ([name],[subject],[Source]) values (N@#张三@#,N@#英语@#,100)
Go
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交叉表语句的实现：
--用于：交叉表的列数是确定的
select name,sum(case subject when @#数学@# then source else 0 end) as @#数学@#,
sum(case subject when @#英语@# then source else 0 end) as @#英语@#,
sum(case subject when @#语文@# then source else 0 end) as @#语文@#
from test
group by name
--用于：交叉表的列数是不确定的
declare @sql varchar(8000)
set @sql = @#select name,@#
select @sql = @sql + @#sum(case subject when @#@#@#+subject+@#@#@#
then source else 0 end) as @#@#@#+subject+@#@#@#,@#
from (select distinct subject from test) as a
select @sql = left(@sql,len(@sql)-1) + @# from test group by name@#
exec(@sql)
go
运行结果：
450)this.width=450" o:title="sql">
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