操纵遨游工具栏的方法，解决spy++无法捕获控件的问题（2）

发布: 2009-4-23 09:50 | 作者: 不详 | 来源: 测试时代采编 | 查看: 320次 | 进入软件测试论坛讨论

            CURSOR = 0xFFFFFFF7,
            ALERT = 0xFFFFFFF6,
            SOUND = 0xFFFFFFF5,
        }

        [DllImport("user32.dll")]
        public static extern int FindWindowEx(int hwndParent, int hwndChildAfter,
            string lpszClass, string lpszWindow);

        public static void msaa(IntPtr hwnd2)
        {
            object ōbj = new object();
            Guid guid = new Guid("{618736E0-3C3D-11CF-810C-00AA00389B71}");
            AccessibleObjectFromWindow(hwnd2, (uint)OBJID.WINDOW, ref guid, ref obj);
            IAccessible accessible = obj as IAccessible;
            accessible = accessible as IAccessible;
            Object[] childs = new Object[accessible.accChildCount];
            int ōbtained = 0;
            try
            {
                AccessibleChildren(accessible, 0, accessible.accChildCount, childs, ref obtained);
            }
            catch (Exception ex)
            {
                Console.WriteLine(ex.Message);
            }
            Console.WriteLine(accessible.accChildCount);
            Console.WriteLine(obtained.ToString());

            for (int i = 0; i < obtained; i++)
            {
                IAccessible child = childs[i] as IAccessible;
                Console.WriteLine(child.get_accName(0));
                Object[] accchilds = new Object[child.accChildCount];
                int result = 0;
                AccessibleChildren(child, 0, child.accChildCount , accchilds, ref result);
                for (int j = 0; j < result; j++)
                {
                    IAccessible jchild = accchilds[j] as IAccessible;
                    Console.WriteLine(jchild.get_accName(0));
                }
            }
        }
    }
}