[ASP.NET]一个实用的弹出窗口函数

领测软件测试网 public static void OpenPopUp(System.Web.UI.WebControls.WebControl opener,string PagePath,string windowName,int Top,int Left,int width,int height)
{
string clientScript;
string windowAttribs;
windowAttribs = "left=" + Left.ToString() + "px," +
"top=" + Top.ToString() + "px," +
"width=" + width.ToString() + "px," +
"height=" + height.ToString() + "px," +
"left=@#+((screen.width -" + width.ToString()+ ") / 2)+@#,";
clientScript = "window.open(@#"+PagePath+ "@#,@#"+
windowName + "@#,@#"+ windowAttribs + "@#);return false;";
opener.Attributes.Add("onClick", clientScript);
}

private void Page_Load(object sender, System.EventArgs e)
{
// 在此处放置用户代码以初始化页面
if(!IsPostBack)
{
OpenPopUp(Button1,"http://www.google.com";);
OpenPopUp(Button2,"http://www.google.com";,"",0,0,300,300);
}
}

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